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HomePearson Edexcel International IGCSE Information and Communication TechnologyPractice Paper
Pearson Edexcel International · IGCSE · Information and Communication Technology

Free Pearson Edexcel International IGCSE Information and Communication Technology
Practice Paper

8 mixed-difficulty practice questions in the style of real Pearson Edexcel International IGCSE papers — answers, mark-scheme-style explanations, and the official exam structure all on one page.

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What the real Pearson Edexcel International IGCSE Information and Communication Technology paper looks like

Paper 1
Objective and short-answer questions covering the breadth of the specification.
Paper 2
Structured and extended-response questions testing depth of understanding.
Total exam time varies by board and tier — typically 2.5 to 3.5 hours.
Grading: See the official board specification for the current grading scale.

Mini practice paper: 6 questions

Mixed-difficulty questions from across the Information and Communication Technology syllabus. Tap "Show answer" after each to check yourself.

Q1 · Difficulty 1/3

Which of the following correctly describes the purpose of run-length encoding (RLE) as a data compression technique?

  1. It removes duplicate files stored on a hard drive
  2. It converts image data from bitmap format into vector format
  3. It stores repeated consecutive data values as a count and a value pair
  4. It reduces colour depth to decrease the number of colours in an image
Show answer & explanation
✓ Answer: CIt stores repeated consecutive data values as a count and a value pair
RLE works by identifying sequences of repeated consecutive values and storing them as a count followed by the value, reducing file size. Option A describes disk cleanup, not compression. Option C describes reducing colour depth, a separate process. Option D describes vector conversion, which is an entirely different representation method.
Q2 · Difficulty 2/3

What is the denary (decimal) value of the binary number 10110011?

  1. 147
  2. 163
  3. 169
  4. 179
Show answer & explanation
✓ Answer: D179
Working from left to right: 128+0+32+16+0+0+2+1 = 179. Option A (169) results from incorrectly adding 128+32+8+1. Option C (163) results from omitting the 16 column. Option D (147) results from a common positional error when misreading bit positions.
Q3 · Difficulty 2/3

A colour in an image is stored using 24-bit colour depth. How many different colours can be represented?

  1. 65 536
  2. 16 777 216
  3. 4 294 967 296
  4. 16 384
Show answer & explanation
✓ Answer: B16 777 216
The number of colours = 2^24 = 16 777 216. Option B (16 384 = 2^14) reflects a student using 14 instead of 24. Option C (2^32 = 4 294 967 296) is the value for 32-bit colour, a common confusion. Option D (65 536 = 2^16) is the value for 16-bit colour depth.
Q4 · Difficulty 2/3

Convert the hexadecimal value 3A into denary. Which answer is correct?

  1. 58
  2. 34
  3. 62
  4. 56
Show answer & explanation
✓ Answer: A58
3A in hex: 3 × 16 + 10 = 48 + 10 = 58. Option A (56) results from calculating 3 × 16 + 8, treating A as 8. Option C (62) results from calculating 4 × 16 - 2, a positional error. Option D (34) results from reading the digits as denary without converting A.
Q5 · Difficulty 3/3

Which of the following binary shifts is equivalent to multiplying an unsigned integer by 4?

  1. A logical right shift of 2 places
  2. A logical left shift of 1 place
  3. A logical left shift of 2 places
  4. A logical right shift of 4 places
Show answer & explanation
✓ Answer: CA logical left shift of 2 places
A logical left shift of n places multiplies an unsigned integer by 2^n. To multiply by 4 (=2^2), a left shift of 2 places is required. Option A (left shift 1) multiplies by 2. Option B (right shift 2) divides by 4. Option D (right shift 4) divides by 16.
Q6 · Difficulty 3/3

A digital audio recording is made with a sample rate of 44 100 Hz, a bit depth of 16 bits, and lasts 10 seconds. What is the uncompressed file size in kilobits (Kbits)?

  1. 4410 Kbits
  2. 7056 Kbits
  3. 441 Kbits
  4. 70 560 Kbits
Show answer & explanation
✓ Answer: B7056 Kbits
File size = sample rate × bit depth × duration = 44 100 × 16 × 10 = 7 056 000 bits = 7056 Kbits (dividing by 1000). Option B omits the bit depth factor. Option C results from not dividing by 1000 to convert to Kbits. Option D results from using 10 × 44 100 only, ignoring bit depth.
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Pearson Edexcel International IGCSE Information and Communication Technology FAQ

What does the Pearson Edexcel International IGCSE Information and Communication Technology exam look like?
The Pearson Edexcel International IGCSE Information and Communication Technology exam is structured across 2 components. Paper 1: Objective and short-answer questions covering the breadth of the specification. Paper 2: Structured and extended-response questions testing depth of understanding. Total exam time varies by board and tier — typically 2.5 to 3.5 hours.
Can I download a free Pearson Edexcel International IGCSE Information and Communication Technology past paper?
Real Pearson Edexcel International past papers are published directly by Pearson Edexcel International on their official website. Kramizo doesn't redistribute copyrighted past papers, but we do generate free AI-written practice papers in the exact same style — same command words, same difficulty tier, same mark conventions. Use this practice paper as warm-up, then time yourself on official past papers before exam day.
How is Pearson Edexcel International IGCSE Information and Communication Technology graded?
See the official board specification for the current grading scale. Kramizo's practice questions are tagged with difficulty 1-3 mapping roughly to the lower, middle, and top grade boundaries you'll encounter in the real exam.