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CIE IGCSE·🧬 Biology·core

CIE IGCSE Biology — Paper 3 (Core Theory)

75 minutes📊 80 marks📄 Paper 3 (Core Theory)
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ℹ️ About this paper: This is an exam-board-aligned practice paper written in the style of CIE IGCSE — not an official past paper. Use it for timed practice, then check against the mark scheme included below. For official past papers, see the exam board's website.
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CIE IGCSE Biology — Paper 3 (Core Theory)

Total marks: 80 · Duration: 75 minutes · Tier: Core

Instructions to candidates

• Answer all questions in both Section A and Section B. • Write your answers in the spaces provided on the question paper. • You may use a calculator. • The number of marks is given in brackets [ ] at the end of each question or part question. • The total number of marks for this paper is 80.

Paper

Section A — Structured Questions (48 marks)

Question 1

(a) The diagram below shows a plant cell as seen under a light microscope.

[Diagram shows a rectangular plant cell with the following structures labelled A, B, C, and D. Structure A points to the cell wall, B to the vacuole, C to the cytoplasm, and D to the nucleus.]

Name the structures labelled A and D.

A: ................................................

D: ................................................
(2 marks)

(b) State two differences between a plant cell and a bacterial cell.

  1. ................................................................................................................................

  2. ................................................................................................................................
    (2 marks)

(c) A student uses a light microscope to observe the plant cell. The eyepiece lens has a magnification of ×10 and the objective lens has a magnification of ×40.

Calculate the total magnification.

Total magnification = ................................................
(1 mark)

(d) The actual length of the cell is 0.05 mm. The student measures the length of the cell in the image as 20 mm.

Calculate the magnification of the image. Show your working.

Magnification = ................................................
(2 marks)


Question 2

The diagram below shows part of the human digestive system.

[Diagram shows the digestive system with the following labelled: mouth, oesophagus, stomach (labelled X), small intestine (labelled Y), large intestine, and rectum.]

(a) Name the organ labelled X.

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(1 mark)

(b) Describe the function of the large intestine.

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(2 marks)

(c) The small intestine is labelled Y. Explain how the structure of the small intestine is adapted for the absorption of digested food.

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(3 marks)

(d) The table below shows the pH in different parts of the digestive system.

Part of digestive system pH
Mouth 7.0
Stomach 2.0
Small intestine 8.5

(i) State which part of the digestive system has an acidic pH.

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(1 mark)

(ii) Suggest why the stomach has a low pH.

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(2 marks)


Question 3

A student investigated the rate of photosynthesis in pondweed by counting the number of bubbles produced in one minute at different light intensities. The results are shown in the table below.

Distance of lamp from pondweed (cm) Number of bubbles in one minute
10 45
20 28
30 18
40 12
50 9

(a) State the independent variable in this investigation.

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(1 mark)

(b) Identify one variable that should be kept constant in this investigation.

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(1 mark)

(c) Describe the relationship between the distance of the lamp from the pondweed and the number of bubbles produced.

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(2 marks)

(d) Explain why increasing the distance of the lamp from the pondweed affects the rate of photosynthesis.

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(2 marks)

(e) Write the word equation for photosynthesis.

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(2 marks)

(f) The student repeated the investigation at 50 cm and obtained a result of 15 bubbles. The original result at 50 cm was 9 bubbles.

Calculate the mean number of bubbles at 50 cm.

Mean = ................................................
(1 mark)


Question 4

The diagram below shows the human breathing system.

[Diagram shows the respiratory system with trachea, bronchi, lungs, ribs, intercostal muscles (labelled P), and diaphragm (labelled Q).]

(a) Name the structures labelled P and Q.

P: ................................................

Q: ................................................
(2 marks)

(b) Describe what happens to the ribs and diaphragm during inhalation (breathing in).

Ribs: ..........................................................................................................................

Diaphragm: ..............................................................................................................
(2 marks)

(c) Explain why the movement of the ribs and diaphragm during inhalation causes air to enter the lungs.

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(3 marks)

(d) The table below shows the percentage composition of inhaled and exhaled air.

Gas Inhaled air (%) Exhaled air (%)
Oxygen 21 16
Carbon dioxide 0.04 4
Nitrogen 78 78
Water vapour variable high

(i) Explain why the percentage of oxygen is lower in exhaled air than in inhaled air.

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(2 marks)

(ii) State why the percentage of nitrogen remains the same in inhaled and exhaled air.

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(1 mark)


Question 5

The diagram below shows a food chain from a grassland ecosystem.

grass → grasshopper → frog → snake → hawk

(a) Identify the producer in this food chain.

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(1 mark)

(b) State the source of energy for all food chains.

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(1 mark)

(c) The grasshopper is a primary consumer. Explain what is meant by a primary consumer.

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(2 marks)

(d) Energy is lost at each stage in a food chain. State two ways in which energy is lost from animals.

  1. ................................................................................................................................

  2. ................................................................................................................................
    (2 marks)

(e) A pyramid of numbers for this food chain would show fewer organisms at higher trophic levels. Explain why there are usually fewer organisms at higher trophic levels.

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(3 marks)


Question 6

A gardener noticed that some tomato plants had yellow leaves. The gardener added nitrate fertiliser to the soil. After two weeks, the leaves became green again.

(a) Suggest why the leaves were yellow before the fertiliser was added.

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(2 marks)

(b) Explain why plants need nitrates.

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(2 marks)

(c) The gardener also noticed aphids (small insects) feeding on the tomato plants. Describe how aphids damage plants.

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(2 marks)

(d) The gardener decided to use a biological control method instead of using a pesticide.

(i) Explain what is meant by biological control.

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(2 marks)

(ii) State one advantage of using biological control instead of pesticides.

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(1 mark)


Section B — Extended Response (32 marks)

Question 7

The human body maintains a constant internal environment through homeostasis. Temperature regulation and blood glucose regulation are two important examples of homeostatic control.

The diagram below shows how body temperature is regulated.

[Diagram shows a flow chart: "Body temperature rises above 37°C" → "Detected by receptors in skin and brain" → "Message sent to brain" → "Response: sweating increases, vasodilation occurs" → "Body temperature decreases back to 37°C"]

(a) Define the term homeostasis.

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(2 marks)

(b) Describe how sweating helps to reduce body temperature.

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(3 marks)

(c) Explain what is meant by vasodilation and how it helps to reduce body temperature.

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(4 marks)

(d) Blood glucose concentration is also regulated by homeostasis. The hormone insulin is involved in this process.

Discuss how the body responds when blood glucose concentration becomes too high after eating a meal containing carbohydrates. In your answer, you should: • explain the role of insulin • describe what happens to excess glucose • explain what would happen if this control system did not work properly.

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(6 marks)


Question 8

A student investigated the effect of temperature on the activity of the enzyme amylase. Amylase breaks down starch into maltose (a sugar).

The student set up five test tubes, each containing starch solution and amylase solution. The test tubes were placed in water baths at different temperatures (10°C, 20°C, 30°C, 40°C, and 50°C). The student tested samples from each tube every minute using iodine solution to see if starch was still present. Iodine solution turns blue-black if starch is present and remains orange-brown if starch is absent.

The results are shown in the table below.

Temperature (°C) Time for starch to be completely broken down (minutes)
10 8
20 5
30 3
40 2
50 Starch still present after 10 minutes

(a) State the substrate and product in this enzyme-controlled reaction.

Substrate: ................................................

Product: ................................................
(2 marks)

(b) Describe the relationship between temperature and the time taken for starch to be broken down between 10°C and 40°C.

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(2 marks)

(c) At 50°C, the starch was still present after 10 minutes. Suggest why the amylase did not break down the starch at this temperature.

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(2 marks)

(d) The student concluded that 40°C was the optimum temperature for amylase activity.

Evaluate this conclusion. In your answer, you should: • explain what is meant by optimum temperature • discuss whether the data supports this conclusion • suggest how the investigation could be improved to provide better evidence • explain the importance of enzyme activity in digestion.

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(9 marks)


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