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CIE IGCSE·🧬 Biology·extended

CIE IGCSE Biology — Paper 4 (Extended Theory)

75 minutes📊 80 marks📄 Paper 4 (Extended Theory)
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ℹ️ About this paper: This is an exam-board-aligned practice paper written in the style of CIE IGCSE — not an official past paper. Use it for timed practice, then check against the mark scheme included below. For official past papers, see the exam board's website.
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CIE IGCSE Biology — Paper 4 (Extended Theory)

Total marks: 80 · Duration: 75 minutes · Tier: extended

Instructions to candidates

• Answer ALL questions in both Section A and Section B. • Write your answers in the spaces provided on the question paper. • You may use a sharp pencil for diagrams and graphs, but answers must be written in black or blue pen. • Calculators may be used in this examination. • The number of marks is given in brackets [ ] at the end of each question or part question. • Section A carries 48 marks and Section B carries 32 marks.


Paper

Section A — Structured Questions (48 marks)

1. Fig. 1.1 shows a section through a dicotyledonous leaf as seen under a light microscope.

[Diagram showing: upper epidermis (A), palisade mesophyll layer (B), spongy mesophyll with large air spaces, vascular bundle with xylem (C) and phloem (D), lower epidermis with guard cells (E) surrounding a stoma]

(a) Name the tissues labelled A and C.

A: ...................................................................

C: ................................................................... [2]

(b) Explain how the structure of tissue B is adapted for its function. [3]

(c) The lower epidermis contains many stomata.

(i) State the process that causes water loss through stomata. [1]

(ii) Describe how guard cells control the opening and closing of stomata. [3]

(d) A student investigated the number of stomata on the upper and lower surfaces of leaves from three different plant species.

Table 1.1 shows the results.

Table 1.1

Plant species Number of stomata per mm² on upper surface Number of stomata per mm² on lower surface
Sunflower 175 325
Water lily 460 0
Pine 50 71

(i) Calculate the percentage of the total stomata found on the upper surface of the sunflower leaf. Show your working. [2]

(ii) Suggest why the water lily has no stomata on the lower surface of its leaves. [2]

[Total: 13 marks]


2. Enzymes are biological catalysts that control metabolic reactions.

(a) Define the term enzyme. [2]

(b) Fig. 2.1 shows the effect of temperature on the rate of an enzyme-controlled reaction.

[Graph showing: rate of reaction on y-axis, temperature (°C) on x-axis from 0 to 60. Curve rises from 0°C, peaks sharply at 40°C (optimum), then drops steeply to near zero by 60°C]

(i) State the optimum temperature for this enzyme. [1]

(ii) Explain why the rate of reaction increases between 10°C and 40°C. [2]

(iii) Explain why the rate of reaction decreases above 40°C. [3]

(c) A student investigated the effect of pH on the enzyme amylase.

Amylase breaks down starch into maltose.

The student: • placed 5 cm³ of starch solution into each of five test tubes • added 2 cm³ of buffer solution to each tube to give pH values of 3, 5, 7, 9 and 11 • added 1 cm³ of amylase solution to each tube • left the tubes at 30°C • tested samples from each tube every minute with iodine solution until no further colour change occurred.

A blue-black colour indicates the presence of starch.

Table 2.1 shows the student's results.

Table 2.1

pH Time for starch to be completely broken down (minutes)
3 no change after 15 minutes
5 8
7 3
9 5
11 no change after 15 minutes

(i) State the pH at which amylase works most effectively. [1]

(ii) Suggest why the starch was not broken down at pH 3. [2]

(iii) Identify one variable that the student controlled in this investigation. [1]

[Total: 12 marks]


3. The human digestive system breaks down large insoluble molecules into smaller soluble molecules.

(a) Complete Table 3.1 to show the products of digestion for each type of food molecule.

Table 3.1

Food molecule Product(s) of digestion
protein
starch
lipid

[3]

(b) Fig. 3.1 represents part of the small intestine.

[Diagram showing: cross-section of small intestine wall with villi projecting into lumen. One villus enlarged showing: epithelial cells, lacteal (X), capillary network (Y), and thin wall of villus]

(i) State the name of structure X and describe its function. [2]

(ii) Explain how structure Y is adapted to absorb the products of digestion efficiently. [3]

(c) After absorption, amino acids are transported to the liver in the hepatic portal vein.

(i) State one use of amino acids in the body. [1]

(ii) Excess amino acids cannot be stored in the body. They are deaminated in the liver.

Describe what happens during deamination. [2]

[Total: 11 marks]


4. Fig. 4.1 shows the human heart.

[Diagram showing: heart with chambers labelled A (right atrium), B (right ventricle), C (left atrium), D (left ventricle); vessels labelled E (vena cava), F (pulmonary artery), G (pulmonary vein), H (aorta); valves shown between atria and ventricles and in arteries]

(a) (i) Name the blood vessels labelled F and H.

F: ...................................................................

H: ................................................................... [2]

(ii) State which chamber, A, B, C or D, has the thickest muscular wall and explain why. [2]

(b) Describe the pathway of blood through the heart during one complete circulation, starting from the vena cava. [4]

(c) Table 4.1 shows the percentage of oxygen in blood at different locations in the body.

Table 4.1

Location Percentage of oxygen in blood
pulmonary vein 19.0
aorta 19.0
vena cava (at rest) 14.0
vena cava (during exercise) 4.5

(i) Explain why the percentage of oxygen in the pulmonary vein and aorta is the same. [2]

(ii) Calculate the percentage decrease in oxygen between the aorta and the vena cava during exercise. Show your working. [2]

[Total: 12 marks]


Section B — Extended Response (32 marks)

5. The spread of infectious diseases is a major global health concern.

Table 5.1 shows information about four different infectious diseases.

Table 5.1

Disease Pathogen type Method of transmission Symptoms
Cholera bacterium contaminated water diarrhea, dehydration
Malaria protoctist vector (mosquito) fever, headache, damage to red blood cells
Influenza virus airborne droplets fever, muscle pain, cough
Athlete's foot fungus direct contact with infected surfaces itching, cracking of skin between toes

(a) Define the term pathogen. [2]

(b) Explain how the body's immune system responds to infection by a pathogen. Your answer should include: • how pathogens are detected by the immune system • the role of white blood cells in fighting infection • how the immune system provides long-term protection against disease. [8]

(c) Discuss the methods that can be used to control the spread of infectious diseases. In your answer, you should refer to specific examples from Table 5.1 and evaluate the effectiveness of different control methods. [6]

[Total: 16 marks]


6. Photosynthesis and respiration are essential processes in living organisms.

Fig. 6.1 shows how the concentration of carbon dioxide in the atmosphere has changed over the past 1000 years.

[Graph showing: CO₂ concentration (ppm) on y-axis from 260 to 420, year on x-axis from 1000 to 2000. Line remains relatively stable around 280 ppm from 1000 to 1750, then rises gradually to 315 by 1950, then rises steeply to 410 by 2020]

(a) State the word equation for photosynthesis. [2]

(b) Describe an investigation you could carry out to show that light is necessary for photosynthesis. Include: • the method you would use • how you would make the test fair • the results you would expect. [6]

(c) Evaluate the impact of the increasing atmospheric carbon dioxide concentration shown in Fig. 6.1 on: • global ecosystems • agricultural food production • the rate of photosynthesis in plants.

In your answer, you should consider both beneficial and harmful effects. [8]

[Total: 16 marks]


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