What volume of carbon dioxide gas is produced at room temperature and pressure when 10.0 g of calcium carbonate reacts completely with excess hydrochloric acid? [Ar: Ca = 40, C = 12, O = 16] CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

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Question

What volume of carbon dioxide gas is produced at room temperature and pressure when 10.0 g of calcium carbonate reacts completely with excess hydrochloric acid? [Ar: Ca = 40, C = 12, O = 16] CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

Accepted Answer

2.4 dm³ — 4 dm³. Award 1 mark for correct calculation. Mr of CaCO₃ = 100. Moles of CaCO₃ = 10.0/100 = 0.1 mol. From equation, 1 mole CaCO₃ produces 1 mole CO₂, so 0.1 moles CaCO₃ produces 0.1 moles CO₂. Volume of CO₂ = 0.1 × 24 = 2.4 dm³ at r.t.p. A is incorrect because it uses 0.01 moles instead of 0.1. C is incorrect due to calculation error. D is incorrect because it assumes 1 mole of CaCO₃ was used.

Answer

12.0 dm³

Answer

0.24 dm³

Answer

24.0 dm³

Answer

2.4 dm³

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