A machine lifts a load of 500 N through a height of 4.0 m in 10 s. What is the useful power output of the machine?

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Question

A machine lifts a load of 500 N through a height of 4.0 m in 10 s. What is the useful power output of the machine?

Accepted Answer

B. 200 W — Work done = 500 N × 4.0 m = 2000 J. Power = 2000 J ÷ 10 s = 200 W. Option A divides force by time without using distance. Option C gives only the work done without dividing by time. Option D multiplies all three values together.

Answer

D. 20 000 W

Answer

C. 2000 W

Answer

B. 200 W

Answer

A. 125 W

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