A bag contains 5 red and 3 blue counters. Two counters are drawn without replacement. What is the probability that the second counter is red, given that the first counter drawn was red?

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Question

A bag contains 5 red and 3 blue counters. Two counters are drawn without replacement. What is the probability that the second counter is red, given that the first counter drawn was red?

Accepted Answer

4/7 — After one red counter is removed, 4 red counters remain out of a total of 7 counters, giving P(second red | first red) = 4/7. Option A uses the original probability before any counter is removed. Option C incorrectly keeps the total at 7 but uses 5 red counters. Option D incorrectly reduces both numerator and denominator but keeps the wrong denominator of 8.

Answer

4/7

Answer

4/8

Answer

5/7

Answer

5/8

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