A surveyor in Trinidad is mapping a straight road that passes through the points P(-1, 3) and Q(5, -9). What is the equation of this road in the form y = mx + c?

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Question

A surveyor in Trinidad is mapping a straight road that passes through the points P(-1, 3) and Q(5, -9). What is the equation of this road in the form y = mx + c?

Accepted Answer

y = -2x + 1 — Award 1 mark for gradient m = (-9 - 3)/(5 - (-1)) = -12/6 = -2. Award 1 mark for substituting into y - y₁ = m(x - x₁): y - 3 = -2(x + 1), giving y = -2x + 1. B is incorrect — wrong sign for gradient. C is incorrect — error in calculating c. D is incorrect — substitution error.

Answer

y = -2x + 1

Answer

y = -2x + 5

Answer

y = -2x - 1

Answer

y = 2x + 5

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