A student heats 500 g of water from 25°C to 75°C using an immersion heater. The specific heat capacity of water is 4200 J/(kg·°C). How much heat energy was transferred to the water?

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Question

A student heats 500 g of water from 25°C to 75°C using an immersion heater. The specific heat capacity of water is 4200 J/(kg·°C). How much heat energy was transferred to the water?

Accepted Answer

105 000 J — Award 1 mark for correct substitution and calculation: Q = mcΔT = 0.5 kg × 4200 J/(kg·°C) × (75 - 25)°C = 0.5 × 4200 × 50 = 105 000 J. A is incorrect — this results from using 25°C instead of the temperature change. C is incorrect — this results from using 75°C instead of the temperature change. D is incorrect — this results from using 100°C or incorrect mass conversion.

Answer

52 500 J

Answer

157 500 J

Answer

210 000 J

Answer

105 000 J

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