A Jamaican farmer uses a hydraulic jack to lift a tractor. The small piston has an area of 5 cm² and the large piston has an area of 100 cm². If a force of 200 N is applied to the small piston, what force is exerted by the large piston?

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Question

A Jamaican farmer uses a hydraulic jack to lift a tractor. The small piston has an area of 5 cm² and the large piston has an area of 100 cm². If a force of 200 N is applied to the small piston, what force is exerted by the large piston?

Accepted Answer

4000 N — Award 1 mark for correct application of Pascal's principle: F₂/F₁ = A₂/A₁, so F₂ = F₁ × (A₂/A₁) = 200 × (100/5) = 200 × 20 = 4000 N. A is incorrect — this divides force by area ratio. B is incorrect — this assumes no force multiplication. C is incorrect — this uses an incorrect multiplication factor of 10.

Answer

200 N

Answer

2000 N

Answer

10 N

Answer

4000 N

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