20.0 cm³ of 0.0500 mol dm⁻³ H₂SO₄ exactly neutralises 25.0 cm³ of NaOH solution. What is the concentration of the NaOH?

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Question

20.0 cm³ of 0.0500 mol dm⁻³ H₂SO₄ exactly neutralises 25.0 cm³ of NaOH solution. What is the concentration of the NaOH?

Accepted Answer

0.0800 mol dm⁻³ — 0800 mol dm⁻³. Award 1 mark. Moles of H₂SO₄ = 0.0200 × 0.0500 = 0.00100 mol; H₂SO₄ + 2NaOH, so NaOH = 0.00200 mol; 0.00200 ÷ 0.0250 = 0.0800 mol dm⁻³. 0.0400 ignores the 1 : 2 ratio.

Answer

0.0400 mol dm⁻³

Answer

0.160 mol dm⁻³

Answer

0.0800 mol dm⁻³

Answer

0.0625 mol dm⁻³

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