A gas has an initial pressure of 200 kPa and volume of 3.0 m³ at constant temperature. The volume is reduced to 1.5 m³. What is the new pressure?

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Question

A gas has an initial pressure of 200 kPa and volume of 3.0 m³ at constant temperature. The volume is reduced to 1.5 m³. What is the new pressure?

Accepted Answer

400 kPa — Using Boyle's Law: P₁V₁ = P₂V₂. So P₂ = (200 × 3.0) / 1.5 = 600 / 1.5 = 400 kPa. Option A is wrong — halving the volume doubles, not halves, the pressure. Option B adds the pressures incorrectly. Option D would be correct only if volume decreased to 1.0 m³.

Answer

300 kPa

Answer

100 kPa

Answer

400 kPa

Answer

600 kPa

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